Câu 1.16 :
a. A = ( 2- $\frac{1}{2}$- $\frac{1}{8}$) : ( 1- $\frac{3}{2}$- $\frac{3}{4}$ )= ( $\frac{16}{8}$- $\frac{4}{8}$- $\frac{1}{8}$) : ( $\frac{4}{4}$- $\frac{6}{4}$- $\frac{3}{4}$ ) = $\frac{11}{8}$ : $\frac{-5}{4}$ = $\frac{-11}{10}$
b. B = 5- $\frac{1+\frac{1}{3}}{1-\frac{1}{3}}$ = 5- $\frac{\frac{3}{3}+\frac{1}{3}}{\frac{3}{3}-\frac{1}{3}}$= 5- $\frac{\frac{4}{3}}{\frac{2}{3}}$= 5- ($\frac{4}{3}. \frac{3}{2}$)= 5-2=3