a) Phản ứng (1): $\overline{\upsilon }=-\frac{1}{2}.\frac{\Delta C_{O_{3}}}{\Delta t}=\frac{1}{3}.\frac{\Delta C_{O_{2}}}{\Delta t}$
Phản ứng (2): $\overline{\upsilon }=-\frac{1}{2}.\frac{\Delta C_{HOF}}{\Delta t}=\frac{1}{2}.\frac{\Delta C_{HF}}{\Delta t}=\frac{\Delta C_{O_{2}}}{\Delta t}$
b) Ta có:
$\overline{\upsilon }=-\frac{1}{2}.\frac{\Delta C_{O_{3}}}{\Delta t}=\frac{1}{3}.\frac{\Delta C_{O_{2}}}{\Delta t}$
→ $\frac{\Delta C_{O_{3}}}{\Delta t}= -\frac{2}{3}.\frac{\Delta C_{O_{2}}}{\Delta t} = -\frac{2}{3}.1,5 . 10^{-4}$ = −1,0×10−4(molL−1s−1)