Câu 1.29 :
a. $\frac{17}{11}- \left ( \frac{6}{5} -\frac{16}{11}\right ) + \frac{26}{5}$ = $\frac{17}{11}$ + $\frac{16}{11} $ - $ \frac{6}{5}$+ $\frac{26}{5}$ = $\frac{33}{11}$+ $\frac{20}{5}$ = 3 + 4 =7
b. $\frac{39}{5}+ \left ( \frac{9}{4} - \frac{9}{5}\right )- \left ( \frac{5}{4} + \frac{6}{7} \right )$= $\frac{39}{5}$- $ \frac{9}{5}$ +$ \left ( \frac{9}{4} - \frac{5}{4}\right )$+ $\frac{6}{7} $= 6+1+$\frac{6}{7} $= 7 + $\frac{6}{7} $=$\frac{49}{7} $ + $\frac{6}{7} $=$\frac{54}{7} $