Ta có:
$\underset{AC}{\rightarrow}$ . $\underset{BC}{\rightarrow}$
= $\underset{AC}{\rightarrow}$ . $\underset{BD}{\rightarrow}$ + $\underset{AC}{\rightarrow}$. $\underset{DC}{\rightarrow}$
= 0 + a .a.cos60° = $\frac{1}{2}$$a^{2}$
Bài 62 : Cho hình thoi ABCD cạnh a và góc A = 120 độ.
Tính vectơ AC . vectơ BC
Ta có:
$\underset{AC}{\rightarrow}$ . $\underset{BC}{\rightarrow}$
= $\underset{AC}{\rightarrow}$ . $\underset{BD}{\rightarrow}$ + $\underset{AC}{\rightarrow}$. $\underset{DC}{\rightarrow}$
= 0 + a .a.cos60° = $\frac{1}{2}$$a^{2}$