Câu 1.
Có : $\widehat{{{A}_{1}}}$ = $\widehat{{{A}_{3}}}$ = 32o (2 góc đối đỉnh)
$\widehat{{{A}_{1}}}$ + $\widehat{{{A}_{2}}}$ = 180o (2 góc kề bù) => $\widehat{{{A}_{2}}}$ = 180o - $\widehat{{{A}_{1}}}$ = 180o -32o = 148o
$\widehat{{{A}_{4}}}$ = $\widehat{{{A}_{2}}}$ = 148o
Có: a//b => $\widehat{{{B}_{1}}}$ = $\widehat{{{A}_{3}}}$ = 32o (2 góc so le trong)
$\widehat{{{B}_{2}}}$ = $\widehat{{{A}_{4}}}$ = 148o (2 góc so le trong)
$\widehat{{{B}_{3}}}$ = $\widehat{{{B}_{1}}}$ = 32o (2 góc đối đỉnh)
$\widehat{{{B}_{4}}}$ = $\widehat{{{B}_{2}}}$ = 148o (2 góc đối đỉnh)