Câu 3.
a) $\frac{5^{16}.27^{7}}{125^{5}.9^{11}}$ = $\frac{5^{16}.(3^{3})^{7}}{(5^{3})^{5}.(3^{2})^{11}}$ = $\frac{5^{16}.3^{21}}{5^{15}.3^{22}}$ = $\frac{5}{3}$
b) $(-0,2)^{2}.5-\frac{2^{13}.27^{3}}{4^{6}.9^{5}}$ = $(\frac{1}{5})^{2}.5-\frac{2^{13}.(3^{3})^{3}}{(2^{2})^{6}.(3^{2})^{5}}$ =$\frac{1}{5}-\frac{2^{13}.3^{9}}{2^{12}.3^{10}}$ = $\frac{1}{5}-\frac{2}{3}$ = $\frac{1}{5}-\frac{2}{3}$ = $-\frac{7}{15}$
c) $\frac{5^{6}+2^{2}.25^{3}+2^{3}.125^{2}}{26.5^{6}}$ = $\frac{5^{6}+2^{2}.(5^{2})^{3}+2^{3}.(5^{3})^{2}}{26.5^{6}}$ = $\frac{5^{6}+2^{2}.5^{6}+2^{3}.5^{6}}{26.5^{6}}$= $\frac{5^{6} .(1 + 2^{2}+2^{3})}{26.5^{6}}$ = $\frac {13}{26}$ = $\frac {1}{2}$